What is the range of the function f (x) = 3x2 + 6x - 8?

Find minimum and max y value because that is what range is

we see it opens up becasue 3 is positive

x value of vertex is - b/2a when you have f (x) = ax^2+bx+c

f (x) = 3x^2+6x-8

vertex is - 6 / (2*3) = - 6/6=-1

find y value by subsituiong it for x

f (-1) = 3 (-1) ^2+6 (-1) - 8

f (-1) = 3 (1) - 6-8

f (-1) = 3-14

f (-1) = - 11

range is from - 11 to infinity