A baseball diamond is a square with sides that are 27.4 m. the pitchers mound is 18.4m from homeplate on the line joining hommeplate and second base. how far is it from the pitchars mound to first base

The diagonal of the diamond measures

d = 27.4 √2

Half of this is

d/2 = 12.35 √2

The distance from the center of the diamond to the pitchers mound is

h = 18.4 - 12.35 √2

Using Pythagorean theorem

x² = (d/2) ² + h²

substituting and solving for x gives the distance between the pitchers mound and the second base