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30 April, 07:16

Write an expression for the next 3 even numbers that are greater than P

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  1. 30 April, 08:35
    0
    We don't know whether ' P ' itself is odd or even.

    - - If ' P ' is even, then the next three [larger] even numbers are

    P+2, P+4, and P+6.

    - - If ' P ' is odd, then the net three [larger] even numbers are

    P+1, P+3, and P+5.
  2. 30 April, 10:27
    0
    Every even number is 2 away from the last.

    0, 2, 4, 6, 8, 10, 12, 14 ... etc.

    If we had an even number p, then the next three even numbers would be

    p+2, p+4, and p+6.

    (If we had an odd number p, then the next three even numbers would be

    p+1, p+3, and p+5. I'm not sure if p is even is implied in the question. Technically the answer would be p - p mod 2 + 2, where p is an interger ... that gets into more technical function stuff, though.)
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