The line width for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometers what is the probability that a line width is greater than 0.62 micrometer?

Question

Mathematics

Kendra Rowe

26 February, 01:59

The line width for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometers what is the probability that a line width is greater than 0.62 micrometer?

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Answers (1)

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Litzy Garza · Answer 1

To solve the question we first calculate the z-score:

z = (x-μ) / σ

where:

μ-mean

σ-standard deviation

thus from the information given we shall have:

z = (0.62-0.5) / 0.05

z=2.4

Thus

P (x>0.62) = 1-P (x<0.62)

=1-P (z=2.4) = 1-0.9918

=0.0082