What is the slope-intercept form of the equation of the line that passes through (7, 3) and is Perpendicular to the line of the equation y = (-1/15) x - 10.

Y = - 1/15x - 10. The slope here is - 1/15. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocl of a number, flip the number and change the sign. So our perpendicular line will need a slope of 15 ... see how I flipped - 1/15 and turned it to - 15/1 ... and changed the sign, making it 15/1 or just 15.

y = mx + b

slope (m) = 15

(7,3) ... x = 7 and y = 3

now we sub and find b, the y int

3 = 15 (7) + b

3 = 105 + b

3 - 105 = b

-102 = b

so ur perpendicular equation is : y = 15x - 102 <==