The sum of three consecutive number odd integers is 18 less than five times the middle number find the three integers

1st number = x

2nd number = x+2

3rd number = x+4

x + x+2 + x+4 = 3x+6

3x+6 = 5 (x+2) - 18

3x+6 = 5x+10-18

3x+6 = 5x-8

3x+14 = 5x

14 = 2x

x = 14/2 = 7

1st number = 7

2nd number = 7+2 = 9

3rd number = 7+4 = 11