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4 October, 08:15

How tall would a tower need to be if the period of a pendulum were 30. seconds

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  1. 4 October, 09:22
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    We use the following expression

    T = 2*pi * sqrt (l/g)

    Where T is the period of the pendulum

    l is the length of the pendulum

    and g the acceleration of gravity

    We solve for l

    l = [T/2*pi]² * g = [30s/2*pi]² * 9.8 [m/s²] = 223.413 m

    The tower would need to be at least 223.413 m high
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