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4 April, 14:02

A ball is thrown upward with an initial velocity of 48 ft/sec from a height 640ft. It's height h, in feet, after t seconds is given by h (t) = - 16t^2 + 48t+640. After how long will the ball reach the ground?

The ball will reach the ground in ___seconds

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  1. 4 April, 14:45
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    We equate h (t) to 0 to find the time at which the ball reaches the ground.

    16t² - 48t - 640 = 0

    t² - 3t - 40 = 0

    t = 8, t = - 5

    Time cannot be negative so second value neglected.

    The ball will reach the ground in 8 seconds.
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