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28 August, 15:52

A canoe is floating down a river with a velocity of 35 meters per minute when it suddenly approaches a waterfall. if the waterfall drop 30 meters, how far put will the canoe land?

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  1. 28 August, 16:56
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    From Newton's law v^2 = u^2 + 2as where a is the acceleration and s is the distance.

    But to go any further, we need to know how fast the vehicle is accelerating

    From v = u + at

    We have a = u/t where the final velocity v = 0

    So in one minute acceleration = (35 / 60) / 60 = 0.0097 ms/2. The first

    experession in bracket is the initial velocity, u, in metres per seconds.

    Hence v^2 = (0.583) ^2 + 2 (0.0097) (30)

    v^2 = 0.3398 + 0.5826 = 0.9224

    v = âš 0.9224 = 0.960m
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