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8 July, 20:36

Isaac throws an apple straight up from 1.0 m above the ground, reaching a maximum height of 35 meters. Neglecting air resistance, what is the ball's velocity when it hits the ground?

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  1. 8 July, 21:15
    0
    So total height = 35+1 = 36 m

    so using the formula, v^2=u^2+2as

    we got = > v^2 = 0 + 2*10*36

    v = 26.83 m/s

    so the final velocity will be 26.83 m/s!
  2. 8 July, 21:21
    0
    26.2005 m/s will be the velocity of the apple right when it hits the ground and the initial velocity would be 25.8235 m/s

    so Vf=26.2005

    and Vi=25.8235

    the velocity difference is due to the apple having an initial height of 1 meter
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