A baseball thrown from the outfield is released from shoulder height at an initial velocity of 29.4 m/s at an initial angle of 30.0 with respect to the horizontal. what is the maximum vertical displacement that the ball reaches during its trajectory?

Question

Aliya Ritter

12 October, 09:04

+5

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Malachi Leach · Answer 1

(v^2) = (u^2) + (2*a*s) where v is final speed

u is initial speed

a is acceleration

s is displacement

U=sin30 * 29.4

v=0

a=9.81