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19 December, 19:02

A force

F acts in the x - direction, its magnitude given by F = ax^2, where x is in meters and a = 5.0N/m^2

. Find the work done by this force as it acts on a particle moving from x = 0 to x = 6.0 m.

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  1. 19 December, 20:48
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    F = ax²

    Integrating force with respect to distance yields work.

    W = ax³/3

    Applying limits:

    W = a/3 [6³ - 0³]

    W = 5/3 (216)

    W = 360 Joules
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