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20 January, 16:33

A pilot increases the take off speed of a jet uniformly from 10 km/hr to 140km/hr in 50 seconds. What is the rate of acceleration?

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  1. 20 January, 17:54
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    Acceleration = (change in speed) / (time for the change)

    Change in speed = (speed at the end) - (speed at the beginning)

    = (140 km/hr) - (10 km/hr) = 130 km/hr

    Time for the change = 50 sec

    Acceleration = (130 km/hr) / (50 sec) = 2.6 km/hr per second.

    To convert to more familiar units:

    (2.6 km/hr-sec) x (1000 m/km) x (1 hr/3600 sec)

    = (2.6 x 1000 x 1) / (3600) km-m-hr / hr-sec-km-sec

    = 0.722 m/s² (about 0.074 of a G)
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