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19 November, 13:20

If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sample change?

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  1. 19 November, 14:36
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    Let as assume the simplest calculation by assuming that the gas is ideal. Therefore, the equation would be PV=nRT, where P is pressure, V is volume, n is the amount of moles of gas, R is the gas constant and T is the absolute pressure. Let us further assume that the amount of gas, n, is constant before and after the change. With that being said, the volume is equal to

    V = nRT/P = kT/P

    The term k is lumped as a constant because they are the same before and after the change. Next, we find the ratio of V1 (before the change) and V2 (after the change).

    V2/V1 = (k*4T/3P) / (kT/P)

    Cancelling out like terms would yield

    V2/V1 = 4/3

    Therefore, the volume after the change is 4/3 of the original volume. This means that the volume increased by (4/3-1 = 1/3 or 33%) 33% after the change of conditions.
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