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11 July, 21:09

A fairgrounds ride spins its occupants inside a flying saucer-shaped container. if the horizontal circular path the riders follow has a 5.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.50 times that due to gravity?

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  1. 11 July, 22:30
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    We know that the acceleration due to gravity g is: g = 9.81 m/s^2

    So the centripetal acceleration (w) is:

    w^2 = 1.5 g / r

    w^2 = 1.5 * (9.81 m/s^2) / 5 m

    w = 1.716 rad / s

    To convert to rad to rev:

    w = (1.716 rad / s) * (1 rev / 2π rad) * (60 s/min)

    w = 16.4 rev/min
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