A particle is moving in a circle of radius R with constant speed. The time period of particle is T=1 second. In a time t=T/6, if the difference between average speed and magnitude of average velocity of particle is 2 m/sec, find the radius of circle

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Susie

2 January, 18:02

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Ryker Jarvis · Answer 1

at t=T/6, total distance covered = 2*pi*r/6 and displacement = r

difference of them = 2*t

so, 2*pi*r/6 - r = 2 (1/6) = 1/3

r=1 / (pi-3) = 7.062