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20 August, 13:49

What s the value of work done on an object when a 10-newton force moves it 30meters and the angle between the force and the displacement at 25 degrees

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  1. 20 August, 17:17
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    Horizontal component = cos (25) * 10 = 9.06 N

    work done = 9.06*30 = 271.9 J
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