A ball of radius 13 has a round hole of radius 6 drilled through its center. find the volume of the resulting solid.

The radius of the ball is 13 units.

Its volume is

V₁ = (4π*13³) / 3

= 9.2028 x 10³ units³

The drilled hole has the approximate shape of a solid cylinder with radius = 6 and length = 26. Its volume is

V₂ = π * (6²) * 26

= 2.9405 x 10³ units³

The volume of the resulting solid is

V₁ - V₂ = 6.2622 x 10³

Answer: 6.2622 x 10³ units³