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21 March, 18:15

Saturated steam at 125 kpa is compressed adiabatically in a centrifugal compressor to 700 kpa at the rate of 2.5 kg⋅s-1. the compressor efficiency is 78%. what is the power requirement of the compressor and what are the enthalpy and entropy of the steam in its final state

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  1. 21 March, 18:48
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    M° = 2.5 kg/sec

    For saturated steam tables

    at p₁ = 125Kpa

    hg = h₁ = 2685.2 KJ/kg

    SQ = s₁ = 7.2847 KJ/kg-k

    for isotopic compression

    S₁ = S₂ = 7.2847 KJ/kg-k

    at 700Kpa steam with S = 7.2847

    h₂ 3051.3 KJ/kg

    Compressor efficiency

    h = 0.78

    0.78 = h₂ - h₁/h₂-h₁

    0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2

    h₂ = 3154.6KJ/kg

    at 700Kpa with 3154.6 KJ/kg

    enthalpy gives

    entropy S₂ = 7.4586 KJ/kg-k

    Work = m (h₂ - h₁) = 2.5 (3154.6 - 2685.2

    W = 1173.5KW
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