A beam of light traveling in air strikes a slab of transparent material. the incident beam makes an angle of 40° with the normal, and the refracted beam make an angle of 26° with the normal. what is the speed of light in the transparent material? (c = 3.0 * 108 m/s)

The angle of the incidence (T) = 40°

Angle of refraction (r) = 26°

→To find the speed of light in the material

From shell's law, we know

n: sin i/sin = speed of light in air/Speed of light in the medium

Sin 40°/sin 60° = 3*10⁸/V

V = 3 * 10⁸ * sin 26°/sin 40°

→ V medium = 2 * 10⁸ m/s.