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20 July, 01:52

A robot probe drops a camera off the rim of a 278 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2. Find the velocity with which it hits the ground. Answer in units of m/s.

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  1. 20 July, 04:34
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    S = u + at u = 0 278 = 3.7t t = 278/3.7 = 75.135 ... v = ut + 0.5at^2 u = 0 v = 0.5 * 3.7 * 75.135^2 = 10,443 m/sec
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