3.6-kg chihuahua charges at a speed of 3.3 m/s what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

Physics is my weakest subject, but it's worth a shot here. Hopefully the answer is right.

velocity (final) = velocity (initial) + acceleration * time

vf = vi + a * t

We want to bring the chihuahua to a stop in half a second. So, velocity (final) = 0 m/s. Its velocity (initial) = 3.3 m/s.

Solving for a, the acceleration.

0 m/s = 3.3 m/s + (a) * 0.5 s

a = - 6.6 m/s^2

Force = mass * acceleration

F = m * a

We know the mass of the chihuahua and we just found the necessary acceleration.

Plug those in.

F = (3.6 kg) * (-6.6 m/s^2)

F = - 23.76 N