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29 April, 22:07

Suppose the wavelength of the light is 450 nm. how much farther is it from the dot on the screen in the center of fringe e to the left slit than it is from the dot to the right slit?

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  1. 30 April, 01:56
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    Since you are looking at a right fringe, the answer is all the time a multiple of the wavelength for the reason that the light makes constructive intrusion. If you are looking at the center (zeroth) fringe, the difference is (450) (0) = 0. For the first maximum, the difference is 450 nm. For the second, it is 450 x 2 = 900 nm. Basically, for the nth maxima, the difference is 450n.
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