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11 August, 15:38

Neglecting air resistance, what maximum height will be reached by an arrow launched straight upward with an initial speed of 35 m/s

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  1. 11 August, 15:50
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    The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.

    The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)

    Plugging everything in, we have h = (0-1225) / (19.6) = 62.5 meters is the maximum height.
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