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12 June, 08:41

Suppose a 0.3-kg mass on a spring that has been compressed 0.10 m has elastic potential energy of 1.0 j. how much further must the spring be compressed to triple the elastic potential energy?

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  1. 12 June, 11:47
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    Not sure what that mass was supposed to do there

    if the spring was compressed 0.1m and has E=1.0 J

    than

    E=F*d/2=k*d*d/2 wich means

    k=2*E/d^2 = 2 * 1J / 0.01m^2 = 200 N/m

    so

    for E=3J we have E=k*d^2/2 = >

    d = sqrt (2*E/k) = sqrt (2*3J/200 N/m) = sqrt (0.03) m = 0.17 m

    this means that the spring has to be compressed an aditional 0.07 m to triple the energy

    (still not sure what that 0.3 kg mass has to do with it)
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