An orange is tossed upward at 21m/s. What is the velocity of the orange 3.5s later. What is the height of the orange at this time. Is the orange still traveling up or is it traveling down.

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Physics

Courtney Dickson

26 May, 05:12

An orange is tossed upward at 21m/s. What is the velocity of the orange 3.5s later. What is the height of the orange at this time. Is the orange still traveling up or is it traveling down.

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Reese May · Answer 1

A) After 3,5s - - >v=v0+gt=21 + (-9,8•3,5) = 21 + (-34,3) = - 13,3m/s; b) The maximum height that the orange reaches is h max=v0^2/2g=22,5m; v^2=sqrt (2gh) = >h=v^2/2g=9,025m. The height of the orange is H=h max-h=13,475m.; c) The orange is traveling down.