Ask Question
25 April, 06:37

A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2. How big is the frictional force on the block? What is the coefficient of friction between the chair and floor?

+1
Answers (1)
  1. 25 April, 10:20
    0
    We can first calculate the net force using the given information.

    By Newton's second law, F (net) = ma:

    F (net) = 25 * 4.3 = 107.5

    We can now calculate the frictional force, f, which is working against the applied force, F (app) (this is why the net force is a bit lower):

    f = F (net) - F (app) = 150 - 107.5 = 42.5 N

    Now we can calculate the coefficient of friction, u, using the normal force, F (N):

    f = uF (n) - - > u = f/F (N)

    u = 42.5/[25 (9.8) ]

    u = 0.17
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A force of 150 N accelerates a 25 kg wooden chair across a wood floor at 4.3 m/s2. How big is the frictional force on the block? What is ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers