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Yesterday, 07:03

A ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor. part a how long will it take the ball to hit the floor?

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  1. S
    Yesterday, 09:05
    0
    Working formula:

    y = v*t + 0.5*a*t^2

    where:

    y = vertical distance = - 1 m

    v = initial velocity = 1.25m/s

    a = acceleration = 9.81 m/s^2

    t = time

    Required: t

    Solution:

    y = v*t + 0.5*a*t^2

    1 = (1.25) * t + 0.5*9.81*t^2

    0 = - 1 + 1.25t + 4.905t^2

    Applying completing the square, we get

    t = 0.342 s, - 0.597s

    Technically, we don't have time with negative value. Thus, the answer is t = 0.342 seconds
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