A jogger accelerates at a constant rate of 1.20 m/s^2 for 3.00 seconds. If her initial speed was 2.50 m/s, find her speed after those 3 seconds of acceleration.

Question

Physics

Trystan Roach

6 July, 21:52

A jogger accelerates at a constant rate of 1.20 m/s^2 for 3.00 seconds. If her initial speed was 2.50 m/s, find her speed after those 3 seconds of acceleration.

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Answers (1)

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Yair Zuniga · Answer 1

Using: v = u + at,

u = initial speed = 2.50 m/s

a = acceleration = 1.2 m/s^2

t = time = 3.00 s

v = 2.5 + 1.2*3

v = 2.5 + 3.6

v = 6.1

Her speed after 3s is 6.10 m/s.