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8 April, 04:47

A spring has a spring constant of 256 n/m. how far must it be stretched to give it an elastic potential energy of 48 j?

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  1. 8 April, 06:53
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    Elastic potential energy=1/2kx^2 (k is constant and x is how far it has to be stretched. So 48=1/2 (256) x^2 which is 0.6123
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