A series circuit contains a 9-volt battery, a 3-ohm resistor and a 2-ohm resistor. What is the voltage drop across the 2-ohm resistor?

3.2 V

3.4 V

3.6 V

3.8 V

Since everything in the circuit is in series ...

- - The total resistance is (3 + 2) = 5 ohms.

- - The voltage across the 3-ohm resistor is 3/5 of the total voltage.

- - The voltage across the 2-ohm resistor is 2/5 of the total voltage.

(2/5) of (9 volts) = 18/5 = 3.6 volts.