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7 January, 15:21

A series circuit contains a 9-volt battery, a 3-ohm resistor and a 2-ohm resistor. What is the voltage drop across the 2-ohm resistor?

3.2 V

3.4 V

3.6 V

3.8 V

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Answers (1)
  1. 7 January, 18:49
    0
    Since everything in the circuit is in series ...

    - - The total resistance is (3 + 2) = 5 ohms.

    - - The voltage across the 3-ohm resistor is 3/5 of the total voltage.

    - - The voltage across the 2-ohm resistor is 2/5 of the total voltage.

    (2/5) of (9 volts) = 18/5 = 3.6 volts.
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