The air temperature in a 28 in. 3 container with a free sliding piston is initially measured at 45 °

f. the temperature is raised to 200 °

f. what is the new volume of the container?

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

V2 = 36.60 in^3