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14 December, 11:07

What is the displacement after 6 seconds when a car is moving at 12m/s and coasts up a hill with a uniform aacceleration of - 1.6 m/s^2

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  1. 14 December, 12:44
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    The kinematic formula using displacement, time, initial velocity, and acceleration:

    x = v t+.5 a t^2

    x = (12m/s) (6s) +.5 (-1.6m/s^2) (6s) ^2

    x = 72m - 28.8m

    x = 43.2 m
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