A shotputter throws the shot with an initial speed of 15.6 m/s at a 30.0 degree angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20m above the ground.

Question

Physics

Kailey Huber

3 August, 20:53

A shotputter throws the shot with an initial speed of 15.6 m/s at a 30.0 degree angle to the horizontal. Calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20m above the ground.

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Mario Ellison · Answer 1

To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t = 1.84 taking the t = 1.84, so the equation will be:

x = 15.6cos (30) * 1.86, x = 24.79m