Ask Question
17 June, 15:50

A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its velocity is 44.0 m/s. What is the acceleration of the rock?

+2
Answers (1)
  1. 17 June, 16:47
    0
    As this happens over twelve seconds, you would take the total difference in velocities and divide it by twelve to find the change per second

    44.0 m/s - 2.0 m/s = 42.0 m/s

    42.0 m/s / 12 s = 3.5 m/s2

    the acceleration of the rock would be 3.5 m/s2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its velocity is 44.0 ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers