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16 May, 00:01

A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work

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  1. 16 May, 03:21
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    With efficiency of 80%, the machine outputs 50000 J. The input to the machine should represent 100%.

    If

    80% - - - 50000 J

    100% - - - ? J

    Solution:

    Input work = (100/80) * 500000 J = 62500 J
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