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28 April, 08:43

A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. determine the acceleration of the bike.

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  1. 28 April, 11:45
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    Given: Change of x is 35.4m, Velocity Final=7.10 m/s, Velocity Initial=0m/s

    Find: Acceleration

    Analysis:

    Vf²=Vi²+2aΔx (Velocity final squared equals Velocity initial squared plus 2 times acceleration times change of x)

    (7.10 m²/s) ² = (0 m/s) ²+2a (35.4 m)

    50.41 m/s² = (70.8 m) a

    a=0.712 m/s²
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