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19 October, 08:13

A box of mass 5.0 kg is accelerated from rest by a force across a floor at a rate of 2.0 m/s2 for 7.0 s. find the net work done on the box.

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  1. 19 October, 11:56
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    W=Fd. Force is not given so we solve for it. F=ma, m=5kg, a=2m/s^2, F=10N. Distance is not given so we solve for it, x=.5a (t^2) =.5 (2) (7x7) = 49m. F=10N, d=49m, W=490J.
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