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22 October, 03:00

A ball having a mass of 0.20 kilograms is placed at a height of 3.25 meters. If it is dropped from this height, what will be the kinetic energy of the ball when it reaches 1.5 meters above the ground?

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  1. 22 October, 06:12
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    EC_1 + EP_1 = EC2 + EP_2

    EC_2 = 0

    EC_2 = EP_1 - EP_2

    EC_2 = mg (H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
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