What is the acceleration of a ball rolling down a ramp that starts from rest and travels 0.9 m in 3 s?

Given:

u = 0, initial velocity

s 0.9 m, distance traveled.

t = 3 s, the time taken.

Let a = the acceleration. Then

s = ut + (1/2) * a*t²

(0.9 m) = 0.5 * (a m/s²) * (3 s) ²

0.9 = 4.5a

a = 0.2 m/s²

Answer: 0.2 m/s²