A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and spring B has a spring constant of 5 N/m. How do the lengths of the springs compare?

The length (extension in spring, x), force applied (F) and the spring constant (k) are related by the following equation:

F = kx

For spring 1:

60 = 4x

so,

x = 15 m

For spring 2:

50 = 5x

so,

x = 10m

Thus the extension in length of second spring will be 5 meters more than the first spring