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9 August, 16:32

At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?

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  1. 9 August, 17:08
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    Hello there.

    At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?

    People would not be thrown off.
  2. 9 August, 19:27
    0
    Let s = rate of rotation

    Let r = radius of earth = 6,400km

    Then solving (s^2) r = g will give the desired rate, from which length of day is inferred.

    People would not be thrown off. They would simply move eastward in a straight line while the curved surface of earth fell away from beneath them.
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Home » Physics » At ground level g is 9.8m/s^2. Suppose the earth started to increase its angular velocity. How long would a day be when people on the equator were just 'thrown off'? Why is the expression 'thrown off' a bad one?
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