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11 November, 15:04

A car travels at uniform acceleration over a distance of 440.0 m. Its final velocity after 20.0 s is 33.0 m/s. What is its initial velocity?

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  1. 11 November, 15:26
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    10. Velocity = acceleration * time = 4 * 9.81 = 39.24m/s

    14. + 3.0m/s (not sure)

    15. Instantaneous velocity (not sure)

    18. s = 0.5 * (u+v) * t, where s=440, u = ?, v=33, t = 20

    u = 11m/s

    20. distance = 23 m, displacement = + 1 m

    25. s = ut + 0.5*a (t^2), where s=25, u = 0, a=9.8, t?

    25 = 0 + 4.9 (t^2)

    t^2 = 5.102

    t = 2.258 s
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