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26 June, 20:39

A 3.00-newton force causes a spring to stretch 60.0 centimeters. Calculate the spring constant of this spring. [Show all work, including the equation and substitution with units.]

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  1. 26 June, 21:51
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    This is a question that utilises Hooke's law, F=kX where F is the magnitude of the force applied, k is the spring constant, and X is the displacement of the end of the spring from its relaxed position.

    We know the force and X so we can rearrange to make k=F/X

    Then, substitute the values for F and X.

    k=3/0.6 = 5 N/m
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