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10 February, 21:04

A gas at 1.00 atm occupies 5.00 l. under what pressure will the volume be 10.0 l if the temperature remains constant?

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  1. 10 February, 22:09
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    P1 = 1.00atm

    P2 = ? atm

    V1 = 5.00L

    V2 = 10.0L

    P1V1 = P2V2 - - > P2 = P1V1 / V2

    P2 = 1.00atm*5.00L / 10.0L

    P2 = 0.50atm
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