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22 January, 09:05

An elevator weighing 2.00 x 10 5 N is supported by a steel cable. What is the tension in the cable when the elevator is accelerated upward at a rate of 3.00 m/s2? (g = 9.81 m/s2) Show your work.

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  1. 22 January, 10:57
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    First, we will get the mass of the elevator:

    Fw = mass * gravitational acceleration

    2 * 10^5 = mass * 9.8

    mass = 20.4 * 10^3 kg

    Now, the total force acting on the elevator can be written as follows:

    Fnet = Tension - Fw

    mass * acceleration = Tension - 2*10^5

    20.4 * 10^3 * 3 = Tension - 2*10^5

    61200 = Tension - 2*10^5

    Tension = (61200) + (2*10^5)

    Tension = 2.61 * 10^5 newton
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