Ask Question
24 July, 19:05

A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what is the horizontal component of the boy's velocity?

+5
Answers (1)
  1. 24 July, 22:06
    0
    Given:

    Launch velocity = 20 m/s

    Launch angle = 25° above he horizontal.

    The horizontal component of velocity is by definition

    Vx = 20*cos (25°) = 18.13 m/s

    Answer: 18.13 m/s (nearest hundredth)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A boy jumps at a speed of 20.0 m/s at an angle of 25.0o above the horizontal. what is the horizontal component of the boy's velocity? ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers