A ball starts from rest and accelerates at 0.500 m/s2 while moving down an inclined plane 9.00 m long. when it reaches the bottom, the ball rolls up another plane, where it comes to rest after moving 15.0m on that plane. (a) what is the speed of the ball at the bottom of the first plane? (b) during what time interval does the ball roll down the first plane? (c) what is the acceleration along the second plane? (d) what is the ball's speed 8.00 m along the second plane?

Question

Physics

Cooper Holder

7 May, 17:55

A ball starts from rest and accelerates at 0.500 m/s2 while moving down an inclined plane 9.00 m long. when it reaches the bottom, the ball rolls up another plane, where it comes to rest after moving 15.0m on that plane. (a) what is the speed of the ball at the bottom of the first plane? (b) during what time interval does the ball roll down the first plane? (c) what is the acceleration along the second plane? (d) what is the ball's speed 8.00 m along the second plane?

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Yasmin · Answer 1

A) final speed = ((initial speed) ^2+2 (accelerarion) (distance)) ^0.5

= ((0) ^2+2 (0.05) (9)) ^0.5=0.949m/s

b) distance=1/2 (initial velocity+final velocity) (time)

time = distance/0.5 (initial velocity+final velocity) = 9/0.5 (0.949) = 19.0s

c) ((0.949) ^2-0) / 30=0.03m/s^2

d) ((0.949) ^2-speed^2) / 2*8=0.03

speed = 0.649m/s