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29 June, 06:04

After an average acceleration of 3.95 m/s2 during 2.25 s, a car reaches a velocity of 15.3 m/s. find the car/'s initial velocity.

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  1. 29 June, 06:32
    0
    Since,

    We have avg. acceleration it can be put in place of accelaration in the given time period.

    v=15.3m/s

    a = 3.95m/s

    t = 2.25 s

    by using,

    a = (v-u) / t

    3.95 = (15.3-u) / 2.25

    (3.95*2.25) - 15.3 = - u

    8.8875-15.3 = - u

    -6.4125 = - u

    ⇒ u = 6.4125 m/s
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