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29 May, 21:50

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

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  1. 29 May, 23:02
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    vf^2 = vi^2 + 2*a*d

    ---

    vf = velocity final

    vi = velocity initial

    a = acceleration

    d = distance

    ---

    since the airplane is decelerating to zero, vf = 0

    ---

    0 = 55*55 + 2 * (-2.5) * d

    d = (-55*55) / (2 * (-2.5))

    d = 605 meters
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